Question

If acceleration ($A$), mass ($M$), velocity ($V$), time ($T$) are the fundamental units, then the dimensions of height will be

• A. $V{T}^{-1}{M}^2$
• B. $AM{T}^{-1}$
• C. $A^{-1}{M}^3{V}^{-1}$
• D. $A{T}^2$

Answer 1

Answer: (D)

$A{T}^2$

Given, acceleration $\left(A\right)$, mass $\left(m\right)$, velocity $\left(v\right)$, time $\left(T\right)$
Hence, $A=\left[L{T}^{-2}\right]\Rightarrow \left[L\right]=\left[A{T}^2\right]$