If actual distance between two places A and B is 110 km and it is represented on a map by 25 mm. Then the scale used is ______ .

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Solution

$∵$ Scale of map = $\frac{S i z e d r a w n}{A c t u a l s i z e} = \frac{25 m m}{110 k m} = \frac{25 m m}{110000000} [∵ 1 k m = 1000000 m m] = \frac{1}{4400000}$
Hence, the scale used is 1 : 4400000.

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If actual distance between two places A and B is 110 km and it is represented on a map by 25 mm. Then the scale used is ______ .

∵ Scale of map = Size drawnActual size=25 mm110 km=25 mm110000000 [∵ 1 km=1000000 mm]=14400000 Hence, the scale used is 1 : 4400000.

$∵$ Scale of map = $\frac{S i z e d r a w n}{A c t u a l s i z e} = \frac{25 m m}{110 k m} = \frac{25 m m}{110000000} [∵ 1 k m = 1000000 m m] = \frac{1}{4400000}$
Hence, the scale used is 1 : 4400000.