wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If AD, BE and CF are the medians of a ABC then (AD2+BE2+CF2):(BC2+CA2+AB2) is equal to


A

4:3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

3:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

3:4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

2:3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

3:4


AB2+AC2=2(AD2+BD2)
c2+b22a24=AD2
Similarly, a2+b22c24=CF2 and a2+c22a2+c24=BE2
Adding a2+b2+c2(a2+b2+c24)=AD2+BE2+CF2
(AD2+BE2+CF2):(a2+b2+c2)=3:4


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solution of Triangles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon