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Question

Ifa=i+j+k,b=i+j,c=iand(axb)xc=λa+μb,thenthevalueofλ+μis?


A

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B

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C

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D

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Solution

The correct option is A

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Explanation of the correct option:

Given, a=i+j+k,b=i+j,c=i

(axb)xc=(a.c)b-(b.c)a=b-a

Given, (axb)xc=λa+μb

b-a=λa+μb

Now if we compare both the sides, we get;

λ+μ=0andλ=-1&μ=1

Therefore, the value of λ+μ=0.

Hence, option (A) is the correct answer.


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