If air is blown with a straw under the pans of a physical balance present in equilibrium position,then that pan :

rises up.

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remains in the same position.

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lowers down.

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rises or lowers depending upon the velocity of air blown.

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Solution

The correct option is C lowers down.
As the air is blown, the speed of air particles is more than the surrounding air. So, there would be an air pressure, $\frac{1}{2} ρ v^{2}$ . So the pan will lower down.

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Question 3

Figure shows a child blowing air with a straw near the opening of another straw which has its other end in a soft drink bottle. It was observed that the level of the soft drink in the straw rises up as soon as air is blown over its open end. Which one of the following best explains the reason for rise in level of the drink?

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If air is blown with a straw under the pans of a physical balance present in equilibrium position,then that pan :

The correct option is C lowers down.As the air is blown, the speed of air particles is more than the surrounding air. So, there would be an air pressure, 12ρv2. So the pan will lower down.

The correct option is C lowers down.
As the air is blown, the speed of air particles is more than the surrounding air. So, there would be an air pressure, $\frac{1}{2} ρ v^{2}$ . So the pan will lower down.