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Question

If all terms in expression A are like the terms in expression B, then which of the following can be an integer value of y?

Expression A Expression B
x(y+1)2+4x3+21x x4+x3+x+1

A
–1
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B
3
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C
–4
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D
2
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Solution

The correct option is A –1
Like terms have the same variables with the same powers.

The exponents of the variables in expression B are 4, 3, 1, and 0.

So, the value of (y+1)2 has to be one of these values.

It is given that y is an integer.
So, (y+1)2 cannot be equal to 3.

Let's compare with the other exponents.
If (y+1)2=4
(y+1)=±2y=1 (or) 3

If (y+1)2=1
(y+1)=±1y=0 (or) 2

If (y+1)2=0
(y+1)=0y=1

Hence, the values of y can be –3, –2, –1, 0, and 1.

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