Question

If all the numbers from $7$ to $59$, which are divisible by $3$ are arranged in descending order then which number will be at $10$th place from the bottom?

• A. $36$
• B. $39$
• C. $30$
• D. $27$

Answer 1

Answer: (A)

$36$

The numbers divisible by $3$ in between $7$ and $59$ in descending order are

$57,54,51,48,45,42,39,\underset{–}{36},33,30,27,24,21,18,15,12,9$
In the following series ${}^{\prime }{36}^{\prime }$ is at the $10$th place from the bottom.

option A