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Question

If all the squared numbers, and numbers, whose sum of digits is 9, from 4 to 65 are removed, then how many numbers will remain?

A
49
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B
55
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C
50
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D
45
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Solution

The correct option is C 50
Total nos. between 4 to 65 =62.
Squared nos. between 4 and 65 =4,9,16,25,36,49,64
Nos. with sum of digits as 9 =18,27,36,45,54,63
Nos. removed =4,9,16,18,25,27,36,45,49,54,63,64
Nos. remaining =6212=50.

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