If - 1- - 2- - 3- n are in A-P- and common difference is d then the value of sin dcosec - 1 cosec -2 - cosec - 2 cosec - 3- - cosec - n-1cosec - n will be-

The correct option is C α _1 α _n [ sin( α #160; _ 2 α #160; _ 1 ) #160; #160; sinα #160; _ 1 sinα #160; _ 2 #160; +sin( α #160 ...

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Sum of n Terms

If α 1, α 2...

Question

If $α_{1}, α_{2}, α_{3} . . . . . . α_{n}$ are in A.P. and common difference is $d$ then the value of $sin (d) (c o s e c α_{1} c o s e c α_{2} + c o s e c α_{2} c o s e c α_{3} + . . . c o s e c α_{n - 1} c o s e c α_{n})$ will be.

sec α_{1} - sec α_{n}

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c o s e c α_{1} - c o s e c α_{n}

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cot α_{1} - cot α_{n}

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tan α_{1} - tan α_{n}

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< α_{1}, α_{2}, . . . . α_{n} \leq \frac{π}{2}

tan α_{1} . tan α_{2} . tan α_{3} . . . . . . tan α_{n} = 1

c o s e c α_{1} . c o s e c α_{2} . c o s e c α_{3} . . . . . . c o s e c α_{n}

α_{1}, α_{2}, α_{3}

α_{n}

sec α_{1} sec α_{2} + sec α_{2} sec α_{3} +

= \frac{tan α_{n + 1} - tan α_{1}}{sin d}

α_{1}, α_{2}, α_{3} \dots . . α_{n}

x^{n} + a x + b = 0

(α_{1} - α_{2}) (α_{1} - α_{3}) \dots . . (α_{1} - α_{n}) =

1, α_{1}, α_{2}, α_{3}, . . ., α_{n - 1}

1. α_{1} . α_{2} . α_{3} . . . α_{n - 1}

1, α_{1}, α_{2}, α_{3}, . . . . ., α_{n - 1}

n = (1 - α_{1}) (1 - α_{2}) (1 - α_{3}) . . . . . (1 - α_{n - 1})

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