If α and α are two points on the hyperbola x2a2−y2b2=1 and the chord joining these two points passes through the focus (ae, 0) then e cosα−β2
A
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B
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C
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D
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Solution
The correct option is A Equation of the chord joining the points α and β on the hyperbola is xacos(α−β2)−ybsin(α+β2)=cos(α+β2) Since this line passes through the focus (ae, 0). We have e cos (α−β2)=cos(α+β2)