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Question

If α and β(α<β) are the roots of the equation x2+bx+c=0, where c<0<b, then

A
0 < α < β
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B
α < 0 < β < |α|
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C
α < β < 0
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D
α < 0 < |α| < β
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Solution

The correct option is B α < 0 < β < |α|
Here D=b24ac>0 because c<0<b.
So roots are real and unequal.
Now, α+β=b<0 and αβ=c<0
Therefore, One root is positive and the other negative, the negative root being numerically bigger.
As α<β,α is the negative root while β is the positive root.
So,|α|>β and α<0<β.

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