If α and β are roots of ax2+bx+c=0, then equation whose roots are αβ,βα, is
A
acx2+(b2+2ac)x+ac=0
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B
acx2−(b2−2ac)x+ac=0
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C
bcx2−(b2−ac)x+ac=0
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D
None of these
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Solution
The correct option is Bacx2−(b2−2ac)x+ac=0 Given α,β are roots off ax2+bx+c=0 S=αβ+βα=α2+β2αβ ⇒S=b2−2acac P=αβ⋅βα=1 ∴ Required equation is acx2−(b2−2ac)x+ac=0 Hence, option B.