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Question

If α and β are roots of ax2+bx+c=0, then equation whose roots are αβ,βα, is

A
acx2+(b2+2ac)x+ac=0
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B
acx2(b22ac)x+ac=0
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C
bcx2(b2ac)x+ac=0
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D
None of these
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Solution

The correct option is B acx2(b22ac)x+ac=0
Given α,β are roots off ax2+bx+c=0
S=αβ+βα=α2+β2αβ
S=b22acac
P=αββα=1
Required equation is acx2(b22ac)x+ac=0
Hence, option B.

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