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Question

If α and β are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of the ellipse is:

A
cosα+cosβcos(αβ)
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B
sinαsinβsin(αβ)
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C
cosαcosβcos(αβ)
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D
sinα+sinβsin(α+β)
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Solution

The correct option is B sinα+sinβsin(α+β)
The equation of a chord joining points having eccentric angles α and β is given by

xacos(α+β2)+ybsin(α+β2)=cos(αβ2)

If it passes through (ae,0) then

ecos(α+β2)=cos(αβ2)

e=cos(αβ2)cos(α+β2)

2sin(α+β2)cos(αβ2)2sin(α+β2)cos(α+β2)=sinα+sinβsin(α+β)

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