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Question

If, α and β are the positive roots of the equation, ax2+bx+c=0, find the equation whose roots are 1α and 1β.

A
ax4+bx2+c=0
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B
None of the above
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C
cx2+bx+a=0
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D
cx4+bx2+a=0
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Solution

The correct option is D cx4+bx2+a=0
Given: α,β are the positive roots of the equation ax2+bx+c=0
To find: Equation with roots 1α and 1β

Let y=1x

x=1y2

Put x=1y2 in given equation,

a(1y2)2+b(1y2)+c=0

ay4+by2+c=0

cy4+by2+a=0

Now, In terms of variables x, the transformed equation becomes:

cx4+bx2+a=0

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