wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

if alpha and beta are the roots of 2x2+ x+3 =0, then equation whose roots are 1-alpha/1+alpha and 1-beta/1+beta is

Open in App
Solution

Dear Student,2x2+x+3=0Here, roots are α and β,Now we know that;α+β=-ba=-12.........(i)and,αβ=ca=32.......(ii)Now,The new quadratic equation has roots which are;1-α1+α and 1-β1+βNow, Summation of roots;1-α1+α+1-β1+β=(1+β)(1-α)+(1-β)(1+α)(1+α)(1+β)=1+β-α-αβ+1+α-β-αβ1+α+β+αβ=2(1-αβ)1+(α+β)+αβNow put value of (α+β) and αβ from (i) and (ii), we get;=2(1-32)1-12+32=-12Summation of roots of new quadratic equation =-12Now,(1-α1+α)×(1-β1+β)=1-α-β+αβ1+α+β+αβ=1-(α+β)+αβ1+(α+β)+αβNow put value of (α+β) and αβ from (i) and (ii), we get;=1+12+321-12+32=32Product of roots of new quadratic equation =32 We can write quadratic equation in the below mentioned form;x2-(sum of roots)x+(product of roots)=0So,x2-(-12)x+32=02x2+x+3=0Which is identical as parent quadratic equation.Regards.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon