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Question

If αandβ are the roots of the equation ax2bx+c=0, then evaluate (α+1)(β+1).

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Solution

Consider the given equation.
ax2bx+c=0
α+β=ba αβ=ca
(α+1)(β+1)=αβ+β+α+1
=ca+ba+1=a+b+ca

Hence, this is the answer.

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