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Question

If α and β are the roots of the equation ax2+bx+c=0. Find the equation whose roots are as given below.
α2+β2,1α2+1β2

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Solution

S=α2+β2+1α2+1β2=(α2+β2)(1+1α2β2)
=b22aca2.a2+c2c2
P=(α2+β2).(α2+β2)α2β2=(b2+2ac)2a2c2
Equation is :
a2c2x2(b22ac)(a2+c2)x+(b22ac)2=0

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