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Question

if α and β are the roots of the equation ax2+bx+c=0 then the sum of the roots of the equation a2x2+(b22ac)x+b24ac=0 is

A
(α2β2)
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B
(α+β)22αβ
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C
α2β+βα24αβ
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D
(α2+β2)
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Solution

The correct option is D (α2+β2)
As α,β are the roots of equation ax2+bx+c=0

then
α+β=ba
αβ=ca

The sum of the roots of the equation is given by,
sum of roots=
b22aca2=(ba)2+2ca=(α+β)2+2αβ=(α2)β22αβ+2αβ(α2+β2)


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