If(alpha) and (beta) are the zeroes of quadratic polynomial 4x? - 5x -1 ,find the valve of (alpha)?beta+alpha(beta)?

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$Assuming your question as If α and β are the zeroes of quadratic polynomial 4 x^{2} - 5 x - 1, find the valve of α^{2} β + {αβ}^{2} Since α and β are the zeroes of quadratic polynomial 4 x^{2} - 5 x - 1 So, α + β = - \frac{Coeff . of x}{Coeff . of x^{2}} = - \frac{(- 5)}{4} = \frac{5}{4} and αβ = \frac{Constant term}{Coeff . of x^{2}} = \frac{- 1}{4} Consider, α^{2} β + {αβ}^{2} = αβ (α + β) = \frac{- 1}{4} \times \frac{5}{4} = \frac{- 5}{16}$

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