wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If α and β are the zeroes of the polynomial 4x2+3x+7, then 1α+1β is equal to:

A
73
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
73
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
37
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
37
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 37
Given: α,β are zeroes of the polynomial 4x2+3x+7
To find the value of 1α+1β

We know that equation ax2+bx+c=0

Then sum of roots =ba and product of roots=ca

From the given quadratic equation,
α+β=34 and αβ=74
Therefore,
1α+1β=α+βαβ

=3474=37

1α+1β=37

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relationship between Zeroes and Coefficients of a Polynomial
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon