Dear Student, f(x)= 3x2-6x+x-2 =0 = 3x(x-2)+1(x-2)=0 (3x+1)(x-2) = 0 Hence zeroes are -1/3 and 2 let α= -1/3 and β= 2 α3+β3 = -127 + 8 =21527
Regards!