Question

If alpha and beta are the zeros of 2x2-5x+7,then find a quadratic polynomial whose zeros are 2alpha+3beta and 2beta+3alpha

Answer 1

NOTE :-
α² + β² can be written as (α + β)² - 2αβ

p(x) = 2x² - 5x + 7
a = 2 , b = - 5 , c = 7

α and β are the zeros of p(x)

we know that ,
sum of zeros = α + β
= -b/a
= 5/2

product of zeros = c/a
= 7/2
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2α + 3β and 3α + 2β are zeros of a polynomial.

sum of zeros = 2α + 3β+ 3α + 2β
= 5α + 5β
= 5 [ α + β]
= 5 × 5/2
= 25/2

product of zeros = (2α + 3β)(3α + 2β)
= 2α [ 3α + 2β] + 3β [3α + 2β]
= 6α² + 4αβ + 9αβ + 6β²
= 6α² + 13αβ + 6β²
= 6 [ α² + β² ] + 13αβ
= 6 [ (α + β)² - 2αβ ] + 13αβ
= 6 [ ( 5/2)² - 2 × 7/2 ] + 13× 7/2
= 6 [ 25/4 - 7 ] + 91/2
= 6 [ 25/4 - 28/4 ] + 91/2
= 6 [ -3/4 ] + 91/2
= -18/4 + 91/2
= -9/2 + 91/2
= 82/2
= 41

-18/4 = -9/2 [ simplest form ]

a quadratic polynomial is given by :-

k { x² - (sum of zeros)x + (product of zeros) }

k {x² - 5/2x + 41}

k = 2

2 {x² - 5/2x + 41 ]

2x² - 5x + 82 -----> is the required polynomial