If α and β are the zeros of the quadratic polynomial x2−3x+2, then a quadratic polynomial whose zeros are 12α+β and 12β+α is?
A
20x2+9x+1
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B
20x2−9x−1
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C
20x2−9x+1
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D
20x2+9x−1
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Solution
The correct option is C20x2−9x+1 given X2−3X+2 sum of the roots is α+β is −b/a that is 3 and product of the roots α∗β is c/a that is 2 so using the same values for the question also.
as the roots given are 1/(2α+β) and 1/(2β+α) so sum of roots on solving is 3(α+β)/(2((α+β)2)(α∗β))=(9/20) product of the roots is 1/(2((α+β)2)+(α∗β))is(1/20)