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Question

If αand β are two real roots of the equation x3px2+qx+r=0 satisfying the relation αβ+1=0, then find the value of r2+pr+q.


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Solution

Solution: For x3+px2+qx+r=0

Sum of the roots α+β+γ=p . . . (1)

αβ+βγ+γα=q . . . (2)

αβγ=r . . . (3) (Given αβ=1)

From equation 3,
(1)γ=r

γ=r

Substituting γ in equation 2

1+(α+β)r=q

α+β=q+1r . . . (4)

Substitute α+β+γ=p

q+1r+r=p

q+1+r2=pr

r2+pr+q+1=0

r2+pr+q=1


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