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Question

If α and β are zeroes of the polynomial 2x2+7x+3, then find the value of α2+β22αβ.

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Solution

2x2+7x+3
α,β are roots
α+β=72,αβ=32
α2+β22αβ=(α+β)22αβ2αβ=(α+β)24αβ=(72)24(32)
α2+β22αβ=254

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