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Question

If α and β are zeroes of the quadratic polynomial f(x)=3x25x2, then find the values of α2β+β2α

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Solution

f(x)=3x25x2
α+β=53,αβ=23
Given, α2β+β2α
=α3+β3αβ
=(α+β)(α2+β2αβ)αβ
=(α+β)(α+β)23αβαβ
=(53)(259+2.)2/3
=52(439)=21516

1097425_1134882_ans_5355f756a5b6400284738d6cdb9b08cf.jpg

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