If alpha and beta order zeros of polynomial 2 X square + 3 X + 5 then find the value of alpha + beta divided by Alpha into beta

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Solution

P(x) = 2x + 3x + 5
alpha + beta = -b / a = -3 / 2
alpha * beta = c / a =5 / 2
=>alpha + beta/ alpha * beta = -3 / 2 /5/2 = -3/ 2 * 2 / 5 = -3 / 5

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If alpha and beta order zeros of polynomial 2 X square + 3 X + 5 then find the value of alpha + beta divided by Alpha into beta

P(x) = 2x + 3x + 5 alpha + beta = -b / a = -3 / 2 alpha * beta = c / a =5 / 2 =>alpha + beta/ alpha * beta = -3 / 2 /5/2 = -3/ 2 * 2 / 5 = -3 / 5 Hope this helps

P(x) = 2x + 3x + 5
alpha + beta = -b / a = -3 / 2
alpha * beta = c / a =5 / 2
=>alpha + beta/ alpha * beta = -3 / 2 /5/2 = -3/ 2 * 2 / 5 = -3 / 5

Hope this helps