If - - -900 and - -2- then cos2 - - sin2 - is

The correct option is C 12 α +β = 90 ^∘ nbsp; ⇒ 2β +β = 90 ^∘ nbsp; ⇒β = 30 ^∘ nbsp; ∴α = 90 ^∘ nbsp; 30 ^∘ nbsp;= 60 ^∘ nbs ...

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If α + β=90...

Question

If $α + β = 90^{0}$ and $α = 2 β,$ then $c o s^{2} α + s i n^{2} β$ is

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\frac{1}{2}

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Similar questions

α + β = 90^{0}

α = 2 β,

{cos}^{2} α + {sin}^{2} β

α + β = 90^{\circ}

α = 2 β

{cos}^{2} α + {sin}^{2} β

α + β = 90^{\circ}

α = 2 β

{cos}^{2} α + {sin}^{2} β

\frac{\sqrt{2} sin α}{\sqrt{1 + cos 2 α}} = \frac{1}{7}

\sqrt{\frac{1 - cos 2 β}{2}} = \frac{1}{\sqrt{10}}, α, β \in (0, \frac{π}{2})

tan (α + 2 β)

tan α = \frac{1}{7}

sin β = \frac{1}{\sqrt{10}}

0 < α, β < \frac{π}{2}

2 β

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