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Question

If α & β(α<β) are the roots of the equation x2+bx+c=0, where c<0<b, then

A
0<α<β
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B
α<0<β<|α|
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C
α<β<0
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D
α<0<|α|<β
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Solution

The correct option is B α<0<β<|α|

α+β=(b1)=vehenceeitherbothrootsarenegativeoroneisveandmagnitudegreaterthan

the+veroot.now

α+β=(c1)=ve

Hence it is confirmed that one

rootisveandotherareis+ve

α<0but|α|>βα<0<β<|α|


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