If α,β and γ are the roots of the equation x3+3x+2=0 , Find the equation whose roots are (α−β)(α−β),(β−γ)(β−α),(γ−α)(γ−β).
x3−9x2−216=0
α,β and γ are the roots of the equation x3+3x+2=0 ________(1)
Using the relation between roots and coefficients, we get
α+β+γ=−ba=0⇒β+γ=−α,
αβ+βγ+γα=ca=3,
αγβ=−da=−2⇒βγ=−2α
Let y=(α−β)(α−γ)
y=(α−β)(α−γ)=α2−αβ−α+β
=α2−α(β+γ)+βγβ+γ=−α,βγ=−2α
=α2−α(−α)+−2α
⇒y=2α2−2α
⇒yα=2α3−2
⇒2α3−yα−2=0___________(2)
To generalize this equation,
Replace α by x, we get
2x3 -yx - 2 = 0 ____________(3)
To get the relation between x and y
Subtracting equation (3) from twice of equation (1)
2x3 -xy - 2 - 2x3 - 6x - 4 = 0
-xy - 6x - 6 = 0
x(6 + y) = - 6
Now replace
x = −66+y in equation (1)
-216(6+y)3 - 186+y + 2 = 0
(y+6)3−9(y+6)2−108=0
y3+9y2−216=0
Replace y by x ⇒ x3+9x3−216=0
x3+9x2−216=0 has roots
(α−β)(α−γ),(β−γ)(β−α),(γ−α)(γ−β)