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Question

If α,β and γ are the roots of the equation x3+3x+2=0 , Find the equation whose roots are (αβ)(αβ),(βγ)(βα),(γα)(γβ).


A

x35x236=0

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B

x39x2216=0

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C

x311x2100=0

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D

x39x2225=0

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Solution

The correct option is B

x39x2216=0


α,β and γ are the roots of the equation x3+3x+2=0 ________(1)
Using the relation between roots and coefficients, we get
α+β+γ=ba=0β+γ=α,

αβ+βγ+γα=ca=3,
αγβ=da=2βγ=2α

Let y=(αβ)(αγ)

y=(αβ)(αγ)=α2αβα+β
=α2α(β+γ)+βγβ+γ=α,βγ=2α

=α2α(α)+2α

y=2α22α

yα=2α32

2α3yα2=0___________(2)

To generalize this equation,

Replace α by x, we get

2x3 -yx - 2 = 0 ____________(3)

To get the relation between x and y

Subtracting equation (3) from twice of equation (1)

2x3 -xy - 2 - 2x3 - 6x - 4 = 0

-xy - 6x - 6 = 0

x(6 + y) = - 6

Now replace

x = 66+y in equation (1)

-216(6+y)3 - 186+y + 2 = 0

(y+6)39(y+6)2108=0

y3+9y2216=0

Replace y by x x3+9x3216=0

x3+9x2216=0 has roots

(αβ)(αγ),(βγ)(βα),(γα)(γβ)


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