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Question

If α,β and γ are the zeroes of the polynomial 2x3+x213x+6 then αβγ=

A
3
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B
3
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C
12
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D
132
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Solution

The correct option is B 3
we have to find,αβγ
Now,From the given Equation:2x³+x²13x+6=0, Where,a=2,b=1,c=(13),d=6

we know that:α+β+γ=ba=12

αβγ=da=62=3

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