Question

If $\alpha ,\beta$ and $\gamma$ are the zeroes of the polynomial $2x^3+x^2-13x+6$ then $\alpha \beta \gamma =$

• A. $3$
• B. $-3$
• C. $\frac{-1}{2}$
• D. $\frac{-13}{2}$

Answer 1

The correct option is B $-3$

Consider the given polynomial.

$2x^3+x^2-13x+6$

Since, $\alpha ,\beta ,\gamma$ are the zeroes of the given polynomial.

We know that,

$\alpha \beta \gamma =-\frac{d}{a}$

$\alpha \beta \gamma =-\frac{6}{2}$

$\alpha \beta \gamma =-3$

Hence, this is the answer.