If α,β and γ are the zeroes of the polynomial f(x)=ax3+bx2+cx+d, then 1α+1β+1γ is _____.
cd
ad
−cd
−ba
Given α,β and γ are the zeroes of the polynomial f(x)=ax3+bx2+cx+d 1α+1β+1γ =βγ+αγ+αβ(αβγ) =(ca)(−da) =−cd
If α,β and γ are the zeroes of the cubic polynomial ax3+bx2+cx+d, then α+β+γ is equal to
If α,β and γ are the zeros of the polynomial f(x)= ax3+bx2+cx+d, then 1α+1β+1γ is: