If $α, β$ and $γ$ are the zeros of the cubic, polynomial $3 x^{3} - 5 x^{2} - 11 x - 3$ , find $α + β + γ$

\frac{5}{3}

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\frac{- 11}{3}

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\frac{- 5}{3}

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Solution

The correct option is D $\frac{5}{3}$
The zeroes of the polynomial $3 x^{3} - 5 x^{2} - 11 x - 3$ are $α, β$ and $γ$
Applying the relation between zeroes and coefficients of a polynomial,
$α + β + γ = \frac{5}{3}$

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Similar questions

α, β

γ

(α + β + γ) = 4, (α β + β γ + γ α) = 1

α β γ = - 6

α = 3, β = 5, γ = 2,

3, - 1, \frac{- 1}{3}

3 x^{3} - 5 x^{2} - 11 x - 3

- \frac{1}{3}

f (x) = 3 x^{3} - 5 x^{2} - 11 x - 3

One of the zeroes of cubic polynomial $(3 x^{3} - 5 x^{2} - 11 x - 3)$ is $\frac{- 1}{3}$ . Find the other zeroes.

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