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If alpha beta and gamma areroots of cubic polynomial of p (x) is equal to 4x cube plus 3 x square minus 5 x square minus 7 then 1 upon alpha plus 1 upon beeta plus 1 upon alpha is equal to

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Solution

If α,β and γ are the zeros of the polynomial f(x)= ax3+bx2+cx+d, then:
1α+1β+1γ = (αβ+βγ+γα)(αβγ) = (ca)(−da) = −cd.
Hence answer is -(-5)/(-7)=-5/7

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