If α,β are complex number such that |α+β|2=|α|2+|β|2+2k, then k=
A
Re(¯¯¯¯αβ)
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B
Re(α+β)
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C
Re(¯¯¯¯α¯¯¯β)
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D
Re(¯¯¯¯α+¯¯¯β)
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Solution
The correct option is CRe(¯¯¯¯αβ) we know that z.¯z=|z|2 ∴|α+β|2=(α+β)×(¯¯¯¯¯¯¯¯¯¯¯¯¯α+β) =(α+β)×(¯α+¯β) =α¯α+β¯β+¯αβ+¯βα =|α|2+|β|2+¯αβ+¯βα comparing with the given equation Re(¯αβ+¯βα)=2k ∴k=Re(¯αβ+¯βα)2
⇒k=Re(¯¯¯¯αβ) (The real part of ¯αβand¯βα are same as they are conjugate of each other)