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Question

If α,β are roots of ax2+bx+c=0, then find the limxα(1+ax2+bx+c)1xα is

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Solution

xα0forax2+bx+c=0 & 1+ax2+bx+c=0+1=1

limxα(1+ax2+bx+c)1xα = y

log y = 1xα log (1+ax^{2} + bx + c )$

00

LHospital

log y = (2ax+b)1+ax2+bx+c1

=2aα+b

y=e2aα+b

1233682_1503500_ans_6526d8f1913748619f15d31916fcaef4.JPG

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