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Question

If α,β are roots of the equation x25x+6=0, then the equation whose roots are (α+3) and (β+3) is

A
2x211x+30=0
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B
x2+11x=0
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C
x211x+30=0
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D
2x222x+60=0
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Solution

The correct options are
B x211x+30=0
D 2x222x+60=0
Given quadratic equation is x25x+6=0
Let α+3=x
α=x3 (replace x by x-3)
So the required equation is
(x3)25(x3)+6=0
x26x+95x+15+6=0
x211x+30=0
(x211x+30)×2=0
2x222x+60=0

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