If - - are roots of the equation x 2- x -1- c -0- the write value of 1-1-

Α, β are the roots of x^2 α(x+1) c=0 ...(i) ⇒α + β = b/a= a and αβ = c/a = (a +c) ...(ii) Now, (1+α)(1+β)=1+(α + β)+αβ =1+a+( a c) =1 c ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Algebra of Complex Numbers

If α, β are r...

Question

If $α, β$ are roots of the equation $x^{2} - α (x + 1) - c = 0, the write value of (1+ α)(1+ β).$

Open in App

Solution

Suggest Corrections

Similar questions

α, β

x^{2} + α x + β = 0

α \neq β

| | x - β | - α | < 1,

α, β

a x^{2} + b x + c = 0

α_{1,} - β

a_{1} x^{2} + b_{1} x + c_{1} = 0

α, α_{1}

α, β

x^{2} - 4 x - 1 = 0

(α^{1 / 3} + β^{1 / 3})

α, β

a x^{2} + b x + c = 0, α_{1}, - β

a_{1} x^{2} + b_{1} x + c_{1} = 0

α, α_{1}

\frac{x^{2}}{\frac{b}{a} + \frac{b_{1}}{a_{1}}} + x + \frac{1}{\frac{b}{c} + \frac{b_{1}}{c_{1}}} = 0

α, β

x^{2} - x - 4 = 0

\frac{1}{α} + \frac{1}{β} - α β

Join BYJU'S Learning Program