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Question

If α, β are roots of the quadratic equation x2x(a2)(a+1)=0 when a is a variable then the least value of α2+β2

A
5
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B
3
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C
4
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D
1
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Solution

The correct option is C 5
α2+β2=(α+β)22αβ
=(a2)2+2(a+1)
=a24a+4+2a+2
=a22a+6
=(a1)2+5
So least value of α2+β2 is 5 when a=1

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