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Question

If α,β are roots of x25x8=0 and tn=αnβn, then the value of t68t45t5 is

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Solution

Given x25x8=0 has roots α,β,
Now,
α+β=5, αβ=8
We know that tn=αnβn
Now,
t68t45t5=(α6β6)+(αβ)(α4β4)5(α5β5)=α5(α+β)β5(α+β)5(α5β5)=(α5β5)(α+β)5(α5β5)=(α5β5)(5)5(α5β5)=1

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