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Question

If α,β are the root of a quadratic equation x23x+5=0, then the equation whose roots are (α23α+7) and (β23β+7) is

A
x2+4x+4=0
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B
x24x+4=0
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C
x2+4x4=0
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D
x2+2x+3=0
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Solution

The correct option is B x24x+4=0
Given α,β are the roots of equation x23x+5=0
So,
α23α+5=0β23β+5=0
α23α=5 and β23β=5
Now,
α23α+7=2 and β23β+7=2

Hence, the quadratic equation whose roots are 2,2 is
(x2)2=0x24x+4=0

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