wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If α,β are the root of a quadratic equation x23x+5=0, then the equation whose roots are (α23α+7) and (β23β+7) is

A
x24x+4=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+2x+3=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+4x4=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+4x+4=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x24x+4=0
Given α,β are the roots of equation x23x+5=0
So,
α23α+5=0β23β+5=0
α23α=5 and β23β=5
Now,
α23α+7=2 and β23β+7=2

Hence, the quadratic equation whose roots are 2,2 is
(x2)2=0x24x+4=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon