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Question

If α,β are the roots of ax2+bx+c=0 and α+β,α2+β2,α3+β3 are in G.P., where =b24ac, then

A
0
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B
b=0
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C
cb0
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D
c=0
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Solution

The correct option is D c=0

CONVENTIONAL APPROACH
(α2+β2)2=(α+β)(α3+β3)
(b22aca2)2=(ba)(b2+3abca3)
4a2c2=acb2ac(b24ac)=0
As a0c=0


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