If α,β are the roots of ax2+bx+c=0 and α+h,β+h are the roots of px2+qx+r=0, then h=
A
−12(ab−pq)
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B
(ba−qp)
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C
12(ba−qp)
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D
none of these
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Solution
The correct option is C12(ba−qp) From the sum and product property of a quadratic equation we have, α+β=−(ba) αβ=ca (α+h)+(β+h)=−qp We replace value of (α+β) in the above equation to get h=12((ba)−(qp)).