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Question

If α,β are the roots of ax2+bx+c=0 and α+k, β+k are the roots of px2+qx+r=0.
Then b24acq24pr is equal to


A

1

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B

(ap)2

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C

0

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D

(pa)2

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Solution

The correct option is B

(ap)2


Given: α,β are the roots of ax2+bx+c=0 and α+k, β+k are the roots of px2+qx+r=0.

Absolute difference of both the roots will be same,
|αβ|=|α+kβk|[(α+k+β+k)24(α+k)(β+k)]=(α+β)24αβq2p24rp=b2a24caq24prp2=b24aca2b24acq24pr=(ap)2


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