If α,β are the roots of ax2+bx+c=0,(a≠0) and α+δ,β+δ are the roots of the equation Ax2+Bx+C=0,(A≠0) for the same constant δ, then
A
b2−4acA2=B2−4ACa2
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B
b2−4aca2=B2−4ACA2
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C
b2−4acb2=B2−4ACA2
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D
b2−4acB2=B2−4ACa2
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Solution
The correct option is Bb2−4aca2=B2−4ACA2 α,β be the roots of ax2+bx+c=0 and α+δ,β+δ are roots of Ax2+Bx+C=0 we know that difference between the roots |α−β|=√b2−4aca similarly |α+δ−β−δ|=√B2−4ACA ∴b2−4aca2=B2−4ACA2