If α,β are the roots of x2−2ax+b2=0 and γ,δ are the roots of x2−2bx+a2=0, then
A
AM of α,β=GM of γ,δ
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B
GM of α,β=AM of γ,δ
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C
α,β,γ,δandinAP$
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D
α,β,γ,δ and in GP
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Solution
The correct options are AGM of α,β=AM of γ,δ CAM of α,β=GM of γ,δ α+β=2a,αβ=b2 γ+δ=2b,γδ=a2 Clearly we can see from equations that α+β2=√γδ √αβ=γ+δ2 Therefore, GM of α,β=AM of γ,δ Hence, options 'A' and 'B' are correct.