If - - are the roots of equation a x 2-1-2 bx -0- then the equation whose roots are 2 -1- and 2 -1- isA- a x2-2 b x-a-0B- b x2-6 a x-9 b-0- a x2-6 b x-9 a-0D- a x2-6 b x-9 a-0

The correct option is C 2αβ 1 /β = 3/β and 2αβ 1 /α = 3/α ...

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Standard XI

Mathematics

Inequalities Involving Modulus Function

If α, β are t...

Question

If $α, β$ are the roots of equation $a (x^{2} - 1) + 2 b x = 0$ , then the equation whose roots are 2 $α - \frac{1}{β} a n d 2 β - \frac{1}{α}$ is

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Solution

The correct option is C

$\frac{2 α β - 1}{β} = \frac{- 3}{β} a n d \frac{2 α β - 1}{α} = \frac{- 3}{α}$

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If α,β are the roots of equation a(x2−1)+2bx=0, then the equation whose roots are 2 α−1β and 2β−1α is

The correct option is C 2αβ−1β=−3β and 2αβ−1α=−3α

If $α, β$ are the roots of equation $a (x^{2} - 1) + 2 b x = 0$ , then the equation whose roots are 2 $α - \frac{1}{β} a n d 2 β - \frac{1}{α}$ is

The correct option is C

$\frac{2 α β - 1}{β} = \frac{- 3}{β} a n d \frac{2 α β - 1}{α} = \frac{- 3}{α}$