If α,β are the roots of the equation 4x2+3x+7=0, then find the value of α2β+β2α
(−16)21
1621
2116
(−21)16
α+β=−34αβ=74α2β+β2α=αβ(α+β) =−34×74 =−2116
If α,β are roots of the 4x2+3x+7=0, then the value of
1α+1βis